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If (p+q)th and (p-q)th terms of a G.P. are m and n respectively, then write its pth term. |
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Answer» ⇒ Let the first term be a and the common ratio be r. ∴ According to the question, ap+q = m. ap-q = n. an = arn-1 ap+q = a.rp+q-1 ap-q = a.rp-q-1 ∴ a.rp+q-1 = m. a.rp-q-1 = n. Multiplying above two equations we get a2r(p+q-1+(p-q-1) = a2r(2p-2) a2r(2p-2) = m.n (ar)2(p-1) = m.n ∴ arp-1 = √m.n ⇒ Pth term is given by a.rp-1 ∴ arp-1 = √m.n |
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