1.

If P.v and E denotes the momentum velocity and K.E. of a particle then

Answer»

`p=(DE)/(dt)`
`p=(dv)/(dt)`
`p=(dE)/(dv)`
`p=(d^(2)E)/(dt^(2))`

SOLUTION :`E=1/2mv^(2)`
DIFFERENTIATING both SIDES w.r.t.v, we have
`(dE)/(dv)=1/2m.2vimplies(dE)/(dv)=P="momentum"`


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