InterviewSolution
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InterviewSolution
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If `P(x)=a x^2+b x+c&Q(x)=-a x^2+dx+c ,a c!=0,`then the equation `P(x)dotQ(x)=0`hasExactly two real rootsAtleast two real rootsExactly four real roots(d) No real roots |
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Answer» Correct Answer - 1 `P(x).Q(x)=(ax^(2)+bx+c)(-ax^(2)+bx+c)` Now, `D_(1)=b^(2)-4ac and D_(2)=b^(2)+4ac` Clearly, ` D_(1)+D_(2)=2b^(2)ge0` `therefore` Atleast one of `D_(1) and D_(2)` is (+ve). Hence, atleast two real roots. Hene, stamement is true. |
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