1.

If p(x) = x^-2x-3 then find p(3)+ p(-1) p(2)​

Answer»

<P>Answer:

p(X)=x^2-2x-3 then if u PUT 3 it's

(3)^2-2(3)-3=0 for -1 its

(-1)^2-2(-1)-3 = 0 for 2 it's

(2)^2-2(2)-3=-3 then the value of

p(3)+p(-1)+p(2) = 0+0-3=-3


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