1.

If P (x, y) is a point equidistant from the points A(6, -1) and B(2, 3), show that x – y = 3.

Answer»

Since P (x, y) is equidistant from A(6, -1) and B(2, 3), then

PA = PB

or PA2 = PB2

(6 – x)2 + (-1 – y)2 = (2 – x)2 + (3 – y)2

(36 + x2 – 12x) + (1 + y2 + 2y) = (4 + x2 – 4x + 9 + y2 – 6y)

37 – 12x + 2y = 13 – 4x – 6y

8x = 8y + 24

x – y = 3

Hence proved.



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