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If P (x, y) is a point equidistant from the points A(6, -1) and B(2, 3), show that x – y = 3. |
Answer» Since P (x, y) is equidistant from A(6, -1) and B(2, 3), then PA = PB or PA2 = PB2 (6 – x)2 + (-1 – y)2 = (2 – x)2 + (3 – y)2 (36 + x2 – 12x) + (1 + y2 + 2y) = (4 + x2 – 4x + 9 + y2 – 6y) 37 – 12x + 2y = 13 – 4x – 6y 8x = 8y + 24 x – y = 3 Hence proved. |
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