1.

If p(y)=3y⁴+3y³- y - 1then p(-1) =? p(-2) =? p(0)=?​

Answer»

Answer:

p(-1) = 0

p(-2) = 25

p(0) =  - 1

Step-by-step explanation:

given,  p(y)=3y⁴+3y³- y - 1

=>  p(-1) = 3(-1)⁴+3(-1)³- (-1) - 1

            = 3(1)+3(-1)+1 - 1

            = 3-3

            = 0

=>  p(-2) = 3(-2)⁴+3(-2)³- (-2) - 1

             = 3(16)+3(-8)+2 - 1

             = 48-24+1

             = 24+1

             = 25

=>  p(0) = 3(0)⁴+3(0)³- (0) - 1

             = - 1


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