1.

If particle mentioned below moves with same velocity which will have highest de-Broglie wavelength ?

Answer»

Neutron
Proton
`beta`-particle
`alpha`-particle

Solution :From de-Broglie wavelength `lambda=(lambda)/(P)=(lambda)/(mv)`
`lambda PROP (1)/(m)`
Particle with LEAST mass will have maximum de-Broglie wavelength.Here ,`beta`-particle (ELECTRON) has least mass hence its de-Broglie wavelength will be maximum


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