1.

If particles are moving with same velocity, then which has maximum de-broglie wavelength ?

Answer»

Proton
`ALPHA`-PARTICLE
Neutron
`BETA`-particle

Solution :As `lambda = h//mv`, of the given particles `beta`-particle is the lightest, so it will have MAXIMUM de-Broglie wavelength.


Discussion

No Comment Found

Related InterviewSolutions