1.

If pH of hydrogen electrode is 10, then what is the potential of it. . .

Answer»

0.59 V
0.00 V
`-0.59V`
`-0.059V`

Solution :`H_((AQ))^(+)+e^(-) to (1)/(2)H_((g))` (reduction)
`E=E^(@)-(0.059)/(N)"LOG"(1)/([H^(+)])`
`=0.0-(0.059)/(1)pH`
`=0-0.059xx10`
`=-0.59V`


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