If potential V = 20/(x^2 + y^2). The electric field intensity for V is(a) /(x^2 + y^2)^2. State True/False.(b) True(c) FalseI got this question during an interview.My question is based upon Relation of E,D,V in chapter Electrostatic Fields of Electromagnetic Theory

If potential V = 20/(x^2 + y^2). The electric field intensity for V is

1.	If potential V = 20/(x^2 + y^2). The electric field intensity for V is(a) /(x^2 + y^2)^2. State True/False.(b) True(c) FalseI got this question during an interview.My question is based upon Relation of E,D,V in chapter Electrostatic Fields of Electromagnetic Theory
Answer» The correct OPTION is (a) /(X^2 + y^2)^2. State TRUE/False. The EXPLANATION is: E = -Grad (V) = -Grad(20/(x^2 + y^2)) = -(-40x i /(x^2 + y^2)^2 – 40(y j)/(x^2 + y^2)^2) = 40(x i + y j)/(x^2 + y^2)^2. Thus the statement is true.

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If potential V = 20/(x^2 + y^2). The electric field intensity for V is(a) /(x^2 + y^2)^2. State True/False.(b) True(c) FalseI got this question during an interview.My question is based upon Relation of E,D,V in chapter Electrostatic Fields of Electromagnetic Theory

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