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If pressure of `CO_(2)` (real gas ) in a container is given by `P = (RT)/(2V - b) - (a)/(4b^(2))`, then mass of the gas in container isA. `11 g`B. `22 g`C. `33 g`D. `44 g` |
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Answer» Correct Answer - C van der Walls gas equation for `n` moles of real gas `(P + (n^(2)a)/(V^(2))) (V - nb) = nRT` `P = (nRT)/(V - nb) - (n^(2)a)/(V^(2)) = (RT)/((V)/(n) - b) - (a)/(V^(2)//n^(2))` (i) Given equation `P = (RT)/(2V - b) - (a)/(4b^(2))` (ii) Comparing (i) and (ii) `n = (1)/(2) = (M)/(M_(0)) = (M)/(44)` `M = 22 g` |
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