1.

If proton and electron have same de-Broglie wavelength then….

Answer»

both will have same kinetic energy
kinetic energy of proton will be more than kinetic energy of electron
kinetic energy of electron will be more than kinetic energy of proton
Both will have same velocity

Solution :de-Broglie wavelength `lambda=(h)/(mv)`
Here `lambda` is same (GIVEN)
`THEREFORE (h)/(m_(p)v_(p))=(h)/(m_(e)v_(e))`
`therefore m_(p)v_(p)=m_(e)v_(e)`
`(v_(p))/(v_(e))=(m_(e))/(m_(p))`
`therefore (E_(p))/(E_(e))=((1)/(2)m_(p)vp^(2))/((1)/(2)m_(2)v_(e)^(2))`
`=(m_(p))/(m_(e))xx((m_(e))/(m_(p)))^(2)=(m_(e))/(m_(p))`
but `m_(e)ltm_(p)` thus `(m_(e))/(m_(p))lt1`
`therefore (E_(P))/(E_(e))lt1 therefore E_(P)ltE_(e)`


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