1.

If proton moves with velocity 10hatims^(-1) in magnetic field having magnitude 5hatj T, magnetic force acting on it is ______ N.

Answer»

`5xx10^(-18)`
`2xx10^(-18)`
`8XX10^(-18)`
`10xx10^(-18)`

Solution :`vecF=q(vecvxxvecB)`
= `1.6xx10^(-19)(10hatixx5hatj)`
= `1.6xx10^(-19)(50hatk)`
`thereforevecF=8xx10^(-18)HATK`


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