if quantity of heat 1163.4 J supplied to one mole of nitrogen gas , at room temperture at constant pressure , then the rise in temperature isA. 54 KB. 28 KC. 65 KD. 8 K

if quantity of heat 1163.4 J supplied to one mole of nitrogen gas , at

1.	if quantity of heat 1163.4 J supplied to one mole of nitrogen gas , at room temperture at constant pressure , then the rise in temperature isA. 54 KB. 28 KC. 65 KD. 8 K
Answer» Correct Answer - D Heat given to the gas at room temperture and at constant temperature , `Q=nCpDeltaT` `therefore1163.4=1xx(7)/(2)RxxDeltaT" " (becauseC_(p)=(7)/(2)R " for diatomic gas")` `"or"" " DeltaT=(2xx1163.4)/(7xx8.31)" " (because R=8.31J"mol"^(-1)K^(-1))` `"or " DeltaT=40K`

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if quantity of heat 1163.4 J supplied to one mole of nitrogen gas , at room temperture at constant pressure , then the rise in temperature isA. 54 KB. 28 KC. 65 KD. 8 K

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