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If R_(1) and R_(2)are the resistance of two solution of equal volume, then the conductance of the mixture in the same conductivity cell is: |
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Answer» `(1)/(2)((1)/(R_1) +(1)/(R_2))` `K_("net") = (V_(1) + V_(2))`, `K_("net") = (G_(1)G^astxxG_(2)G^astV)/(2V)` , `K_("net") = (1)/(2)((1)/(R_(1)+ (1)/(R_(2))))G^ast = G_("net") G^ast` |
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