1.

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is:

Answer»

`(4pi G)/(3gR)`
`(pi Rg)/(12G)`
`(3g)/(4pi RG)`
`(3PI R)/(4gG)`

SOLUTION :`g=(GM)/(R^(2))=(G)/(R^(2))XX(4)/(3)pi R^(3)RHO`
`thereforerho=(3g)/(4pi RG)`
So correct choice is (c ).


Discussion

No Comment Found

Related InterviewSolutions