1.

If r.m.s. speed of gaseous molecules is x cm s^(-1) at a pressur eof p atm, their r.m.s. at a pressure of2 atmand constant temperature will be

Answer»

x
2x
4x
`x//4`

Solution :`u = sqrt((3RT)/( M)) = sqrt((pV)/( M))`
As temperature is CONSTANT, pV is constant. THEREFORE, r.m.s. speed is constant EVEN if PRESSURE is doubled.


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