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If radius of ""_(13)^(27)Al is 3.6 Fermi, then radius of ""_(52)^(125)Te is nearly

Answer»

4 Fermi
5 Fermi
6 Fermi
8 Fermi

Solution :`R=R_(0) A^(1//3) rArr R alpha A^(1//3)`
`R_(2)/R_(1)=(A_(2)/A_(1))^(1//3)=((125)/(27))^(1//3)`
`R_(2)/R_(1)=5/3 rArr R_(2)=5/3 XX R_(1)=5/3 xx 3.6`
`R_(2)=6" Fermi"`


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