1.

If radius of circular paths followed by one proton and one alpha-particle, in the plane, perpendicular to uniform magnetic field, are equal then ratio of their momenta is _____ .

Answer»

`1:1`
`2:1`
`1:2`
`1:4`

SOLUTION :Equal radius of circular parth,
`r=(mv)/(Bq)=p/(Bq)`
`therefore` In p = BQR, B and r same
`thereforeppropq`
`thereforep_(p)/p_(ALPHA)=q_(p)/q_(alpha)=e/(2e)=1/2`
`thereforep_(p):p_(alpha)=1:2`


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