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If radius of first orbit in hydrogen atom is 0.53Å, then what will be the radius of fourth orbit? |
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Answer» Solution :`r_(N)propn^(2)` `:.(r_(1))/(r_(2))=(n_(1)^(2))/(n_(2)^(2))` `:.r_(2)=(n_(2)^(2))/(n_(1)^(2)).r_(1)=(4^(2))/(1^(2)).(0.53)` `:.r_(2)=(16)/(1)(0.53)=8.48Å` |
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