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If ratio of threshold frequencies of two metals is 1:3 ,ratio of their work function is ……

Answer»

`1:3`
`3:1`
`4:16`
`16:4`

SOLUTION :`(phi_(1))/(phi_(2))=(hv_(0_(1)))/(hv_(0_(2)))=(v_(0_(1)))/(v_(0_(2)))`
`therefore (phi_(1))/(phi_(2))=(1)/(3)`


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