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If `s=4t+(1)/(t)` is the equation o motion of a particle, then the acceleration when velocity vanishes, is |
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Answer» Correct Answer - B We have, `s=4t+(1)/(t)implies(ds)/(dt)=4-(1)/(t^(2))and (d^(2)s)/(dt^(2))=(2)/(t^(3))` Now, Velocity = `0 implies (ds)/(dt)=0implies 4-(1)/(t^(2))=0impliest=(1)/(2)` `therefore ("Acceleration at t ="(1)/(2))=((d^(2)s)/(dt^(2)))_(t=(1)/(2))=(2)/(((1)/(2))^(3))=16` |
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