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If `S(g)+e^(-) rarr S^(1-)(g), Delta H = -207.6 KJ` `S(g) + 2e^(-) rarr S^(2-)(g), Delta H = +335.2 KJ`. The enthalpy for the reaction `S^(1-)(g)+e^(-) rarr S^(2-)(g)`:A. `+127.6 KJ`B. `-127.6 KJ`C. `+542.8 KJ`D. `-641.8 KJ` |
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Answer» Correct Answer - C `Delta H = H_(P-H_(R))` |
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