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If S + O_(2) rarr SO_(2), Delta H = -298.2 kJ SO_(2) + (1)/(2) O_(2) rarr SO_(3), Delta H = -98.2 kJ SO_(3) + H_(2)O rarr H_(2)SO_(4), Delta H = -130.2 kJ H_(2) + (1)/(2) O_(2) rarr H_(2)O, Delta H = -287.3 kJ the enthalpy of formation of H_(2)SO_(4) at 298 K will be |
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Answer» `- 433.7 kJ` `H_(2) (G) + S + 2O_(2) rarr H_(2)SO_(4) DELTA H = ?` (i) `(S + O_(2) rarr SO_(2) Delta H = - 298.2 kJ mol^(-1)` (ii) `SO_(2) + (1)/(2) O_(2) rarr SO_(3) Delta H = - 98.2 kJ mol^(-1)` (iii) `SO_(2) + (1)/(2) O_(2) rarr SO_(3) Delta H = - 130.2 kJ mol^(-1)` (iv) `H_(2) + (1)/(2) O_(2) rarr H_(2)O Delta H = - 287.3 kJ mol^(-1)` ADD eqns. (i), (ii), (iii) and (iv), `H_(2) + S + 2O_(2) rarr H_(2)SO_(4) Delta H = -813.9 kJ` |
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