1.

If scattering angle theta and impact parameter b are related to each other by the relation b=(Z e^(2) cot ""theta/2)/(4pi epsi_(0) (1/2 mv^(2))) then angle of scattering for zero impact parameter will be

Answer»

`0^(@)`
`90^(@)`
`180^(@)`
`45^(@)`

SOLUTION :`b=(ze^(2) cot""theta/2)/(4PI epsi_(0) [1//2 mv^(2)])`
If b=0, then
`ze^(2), cot theta//2=0`
so cot `theta//2=0, theta/2=90^(@) therefore theta=180^(@)`


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