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If `(sec^(2)70^(@)-cot^(2)20^(@))/(2(co s ec^(2)59^(@)-tan^(2)31^(@)))=(2)/(m)`, then m is equal toA. 2B. 3C. 4D. 1 |
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Answer» Correct Answer - c `(sec^(2)70^(@)-cot^(2)20^(@))/(2(co s ec^(2)59^(@)-tan^(2)(90^(@)-59^(@))))=(2)/(m)` `(sec^(2)70^(@)-cot^(2)(90^(@)-70^(@)))/( 2(cose c^(2)59^(@)-tan^(2)(90^(@)-59^(@))))=(2)/(m)` `(sec^(2)70^(@)-tan^(2)70^(@))/(2(co s ec^(2)59^(@)-tan^(2)(90-59^(@))))=(2)/(m)` `=(1)/(2)=(2)/(m)[sec^(2)theta-tan^(2)70^(@) co s ec^(2)theta-cot^(2)theta =1]` `m=2xx2=4` |
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