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If $sec\theta + tan\theta$ = $2+\sqrt{5}$ , then the value of $sin\theta$ is $(0^{0} \leq \theta \leq 90^{0})$1). $\frac{\sqrt{3}}{2}$2). $\frac{2}{\sqrt{5}}$3). $\frac{1}{\sqrt{5}}$4). $\frac{4}{5}$ |
Answer» RIGHT ANSWER for this QUESTION is $\frac{2}{\sqrt{5}}$ | |