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If sec theta+tan theta=p then prove tan theta = p^2 -1÷2p |
Answer» Step-by-step explanation:Given : secθ + tanθ = p ...(i) We KNOW that, sec²θ - tan²θ = 1 (secθ + tanθ)(secθ - tanθ) = 1 p(secθ - tanθ) = 1 secθ - tanθ = 1/p ...(ii) Subtracting (i) and (ii), we GET
2tanθ = p - 1/p 2tanθ = (p² - 1)/p tanθ = (p² - 1)/2p Hence, PROVED !! |
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