1.

If sec theta+tan theta=p then prove tan theta = p^2 -1÷2p​

Answer»

Step-by-step explanation:

Given : secθ + tanθ = p ...(i)

We KNOW that,

sec²θ - tan²θ = 1

(secθ + tanθ)(secθ - tanθ) = 1

p(secθ - tanθ) = 1

secθ - tanθ = 1/p ...(ii)

Subtracting (i) and (ii), we GET

2tanθ = p - 1/p

2tanθ = (p² - 1)/p

tanθ = (p² - 1)/2p

Hence, PROVED !!



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