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If sectheta =2x & ytantheta=2 then2(x^2-1/y^2) |
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Answer» ER : GIVEN that, Now, b²x² - a²y² = b²(a secθ)² - a²(b tanθ)² = b²(a² sec²θ) - a²(b² tan²θ) = a²b² sec²θ - a²b² tan²θ = a²b² (sec²θ - tan²θ) = a²b² [∵ sec²θ - tan²θ = 1] #MarkAsBrainliest |
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