1.

If sectheta =2x & ytantheta=2 then2(x^2-1/y^2)​

Answer» ER :

GIVEN that,

X = a secθ and y = B tanθ

Now, b²x² - a²y²

= b²(a secθ)² - a²(b tanθ)²

= b²(a² sec²θ) - a²(b² tan²θ)

= a²b² sec²θ - a²b² tan²θ

= a²b² (sec²θ - tan²θ)

= a²b² [∵ sec²θ - tan²θ = 1]

#MarkAsBrainliest



Discussion

No Comment Found