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If set A has 10 elements, set B has 20 elements, 5 elements are common to both then find the number of elements in X∪Y.(a) 10(b) 15(c) 20(d) 25The question was posed to me in examination.This key question is from Practical Problems on Union and Intersection of Two Sets topic in division Sets of Mathematics – Class 11

Answer» CORRECT CHOICE is (d) 25

To explain: We know, n (A ∪ B) = n (A) + n (B) – n (A ∩ B)

Given, n (A) = 10, n (B) = 20, n (A ∩ B) = 5.

n (A ∪ B) = 10 + 20 – 5 = 25.


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