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If `sin^(-1)(x/5)+cose c^(-1)(5/4)=pi/2`then the value of x is:(1) 1 (2)3 (3) 4(4) 5 |
Answer» `sin^-1(x)=cosec^-1(1/x)` `cosec^-1 5/4= sin^(-1)4/5=0` `sin^-1(x/5)+theta=pi/2` `sin^-1(x/5)+theta=pi/2` `sin^-1(x/5)=pi/2-theta` `x/5=sin(pi/2,-theta)` `x/5=costheta` `x/5=3/5` `x=3` |
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