The value of `sin^(-1)(sin12)+sin^(-1)(cos12)=`

1.	The value of `sin^(-1)(sin12)+sin^(-1)(cos12)=`
Answer» `sin^-1(sin12)+cos^-1(cos12)` Here, we have to convert `sin12` into a value from `-pi/2` to ` pi/2` and `cos12` into a value from `0` to `pi`. We can write, `sin^-1(sin12)+cos^-1(cos12) = sin^-1(sin(12-4pi))+cos^-1(cos(4pi-12))` `=12-4pi+4pi-12 = 0` `:. sin^-1(sin12)+cos^-1(cos12) =0`

Discussion

`tan^(-1)[(cosx)/(1+sinx)]`is equal to`pi/4-x/2,forx in (-pi/2,(3pi)/2)``pi/4-x/2,forx in (-pi/2,pi/2)``pi/4-x/2,forx in (-pi/2,pi/2)``pi/4-x/2,forx in (-(3pi)/2,pi/2)`
The value of `sin^(-1)(sin12)+sin^(-1)(cos12)=`
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