InterviewSolution
`NPI+(pi)/2LT THETA lt N pi +(pi)/4,, n in Z``n pi +(3pi)/2 lt theta lt n pi +(5PI)/4, n in Z``n pi +(pi)/4 lt theta lt n pi +(3pi)/4, n in Z``n pi +(3pi)/4lt theta lt n pi +(5pi)/4, n in Z`
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