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If `sin^(3) theta+sin theta cos theta+ cos^(3) theta=1`, then `theta` is equal to `(n in Z)`A. `2 n pi`B. `2n pi +pi/2`C. `2npi-pi/2`D. `npi` |
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Answer» Correct Answer - A::B `(sin^(3) theta+cos^(3)theta)-(1-sin theta cos theta)=0` or `(sin theta + cos theta)(1-sin theta cos theta)-(1-sin theta cos theta)=0` or `(1-sin theta cos theta) (sin theta + cos theta-1)=0` If `sin theta cos theta=1` `rArr 2 sin theta cos theta =2` `rArr sin 2 theta=2` (not possible) `rArr sin theta + cos theta=1` `rArr cos (theta-pi/4)=1/sqrt(2)` `rArr theta-pi/4=2npi pm pi/4, n in Z` `rArr theta=2npi` or `2npi+pi/2` |
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