If `sin(sin^(-1)(1/5)+cos^(-1)(x))=1` Find the value of x

1.	If `sin(sin^(-1)(1/5)+cos^(-1)(x))=1` Find the value of x
Answer» We have, `sin(sin^(-1)1/5+cos^(-1)x)=1` `rArr sin^(-1)1/5+ cos^(-1)x=sin^(-1)1=pi/2`. `rArr cos^(-1)x=(pi/2-sin^(-1)1/5)` `rArr cos^(-1)x=cos^(-1)1/5 rArr x=1/5`. Hence, `x=pi/4`.

Discussion

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