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If sin θ + cos θ = 1, then the value of sin 2θ is equal to(A) 1 (B)1/2 (C) 0 (D) –1 |
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Answer» Answer is (C) Given, sin θ + cos θ = 1 Sq. both side (sin θ + cos θ)2 = 12 sin2 θ + cos2 θ + 2sin θ .cos θ = 1 1 + 2sin θ .cos θ = 1 2sin θ .cos θ = 1 -1 = 0 sin 2θ = 0 (sin 2θ = 2sin θ .cos θ ) |
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