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if `sin(theta+18^(@))=cos60^(@)(0^(@) lt theta lt 90^(@))`, then the value of cos`5theta` isA. `(1)/(2)`B. 0C. `(1)/(sqrt(2))`D. 1 |
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Answer» Correct Answer - a `sin(theta+18^(@))=cos60^(@)` `theta+18^(@)+60^(@)=90^(@)` `theta=12^(@)` `rArrcos5theta=cos60^(@)=(1)/(2)` |
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