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If `sin(theta+30^(@))=(3)/(sqrt12)` then findA. `(1)/(4)`B. `(3)/(4)`C. `(sqrt3)/(4)`D. `(1)/(2)` |
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Answer» Correct Answer - b `sin(theta+30^(@))=(3)/sqrt(12)=(3)/(2sqrt(3))=sqrt(3)/(2)sin(theta+30^(@))=sin60^(@)` `therefore theta=30^(@)` `cos^(2)theta=cos^(2)30^(@)` `=((sqrt(3))/(2))^(2)` `=(3)/(4)` |
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