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If `(sin theta+cos theta)/(sin theta-cos theta)` then the value of `sin^(4)theta` isA. `(16)/(25)`B. `(2)/(5)`C. `(1)/(5)`D. `(3)/(5)` |
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Answer» Correct Answer - a `(sin theta+cos theta)/(sin theta-cos theta)=(3)/(1)` find `sin^(4)theta=`? `(sin theta+cos theta)/(sin theta-cos theta)=(3+1)/(3-1)` `rArr tan theta=2` `tan theta=("perpendicular")/("Base")=(2)/(T)` `rArr sin^(4)theta=((2)/sqrt(5))^(2)=16//25` |
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