1.

If `(sin theta+cos theta)/(sin theta-cos theta)` then the value of `sin^(4)theta` isA. `(16)/(25)`B. `(2)/(5)`C. `(1)/(5)`D. `(3)/(5)`

Answer» Correct Answer - a
`(sin theta+cos theta)/(sin theta-cos theta)=(3)/(1)`
find `sin^(4)theta=`?
`(sin theta+cos theta)/(sin theta-cos theta)=(3+1)/(3-1)`
`rArr tan theta=2`
`tan theta=("perpendicular")/("Base")=(2)/(T)`
`rArr sin^(4)theta=((2)/sqrt(5))^(2)=16//25`


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