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If sin theta = root 6 then find the value of cos theta and tan theta |
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Answer» cos theta = √7tan theta = √6 / √7Step-by-step explanation:GIVEN, SIN theta = √6We know that, Trigonometry is applied in the right triangles. Thus the given triangle is right angled triangle. And, sin theta = Perpendicular / HypotenuseAlso, sin theta = √6 = √6/1Then, We get, Perpendicular /HYPOTENUSE = √6/1So, let Perpendicular = x√6 and Hypotenuse = 1x, where x is the constant by which both 1 and √6 is MULTIPLIED. Now, applying Pythagoras theorem, we get, (Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2=> (1x)^2 = (x√6)^2 + (Base)^2=> x^2 = 6x^2 + (Base)^2=> (Base)^2 = 7x^2=> Base = √7x^2 = x√7Now, Cos theta = Base/Hypotenuse = x√7 / 1x = √7 / 1 = √7Tan theta = Perpendicular/Base = x√6 / x√7 = √6 / √7 |
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