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If `sin(x +3alpha)=3 sin (alpha-x)`, thenA. `tan x = tan alpha`B. `tan x = tan^(2)alpha`C. `tan x = tan^(3)alpha`D. `tan x=3 tan alpha` |
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Answer» Correct Answer - C `sin (x+3alpha)=3 sin (alpha - x)` `rArr sin x cos 3alpha + sin 3 alpha cos x = 3 (sin alpha cos x - sin x cos alpha)` `rArr sin x(cos 3alpha + 3 cos alpha) = cos x(3 sin alpha - sin 3 alpha)` `rArr tan x = (4sin^(3)alpha)/(4 cos^(3)alpha)=tan^(3)alpha` |
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