1.

If sin x – cos x = 0, 0° < x < 90° then the value of (sec x + cosec x)2 is:1. 82. 43. 104. 6

Answer» Correct Answer - Option 1 : 8

Given

sin x – cos x = 0

Calculation

sin x – cos x = 0

⇒ sinx = cosx

⇒ sinx = sin(90° - x)

⇒ x = 90° - x

⇒ 2x = 90°

⇒ x = 45°

Now,

(sec x + cosec x)2 

= (sec 45° + cosec 45°)2

= (√2 + √2)2

= (2√2)2

= 8


Discussion

No Comment Found

Related InterviewSolutions