1.

If \(\sin x = \frac{3}{5}\), 0 ≤ x ≤ 90º, then the value of \(\cot x.\sec x\) is:1. \(\frac{5}{3}\)2. \(\frac{3}{5}\)3. \(\frac{4}{5}\)4. \(\frac{3}{4}\)

Answer» Correct Answer - Option 1 : \(\frac{5}{3}\)

Given:

Sinx = 3/5 

Formula Used:

sinθ = perpendicular/hypotenuse 

cosθ = Base/hypotenuse

cotθ = cosθ/sinθ  

Calculation:

cotx × secx = (cosx/sinx) × 1/cosx = 1/sinx 

⇒ cotx × secx = 1/(3/5) = 5/3

∴ The value of  ​\(\cot x.\sec x\) is 5/3



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