1.

If $sin17^{0}$ = $\frac{x}{y}$, then $sec 17^{0} - sin 73^{0}$ is equal to1). $\frac{y}{(\sqrt{y^{2}-x^{2}})}$2). $\frac{y^{2}}{(x\sqrt{y^{2}-x^{2}})}$3). $\frac{x}{(y\sqrt{y^{2}-x^{2}})}$4). $\frac{x^{2}}{(y\sqrt{y^{2}-x^{2}})}$

Answer»

Its TOUGH but OPTION 4 SEEMS CORRECT



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