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If `sintheta_1sintheta_2-costheta_1costheta_2+1=0,`then the value of `tan((theta_1)/2)cot((theta_2)/2)`is equal to`-1`(b) 1(c) 2 (d) `-2`A. `a^(2)+b^(2)ge4`B. `a^(2)+b^(2)le4`C. `a^(2)+b^(2)ge3`D. `a^(2)+b^(2)le2` |
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Answer» Correct Answer - B `sintheta_(1)-sin theta_(2)=a,cos theta_(1)+cosheta_(2)=b` `rArr a^(2)+b^(2)=2+2cos(theta_(1)+theta_(2))` `rArr 0lea^(2)+b^(2)le4` |
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