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If sintheta sin(2alpha+theta)sin(4alpha + theta)...sin(2(n-1)alpha+theta)=(sinntheta)/(2^(n-1)) where 2nalpha=pi then cot(theta)+cot(2alpha+theta)+cot(4alpha+theta)+.......+cot(2n-1)alpha+theta)= |
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Answer» `-ncot ntheta` |
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