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If sinx = 3/5, then find the value of 3sin2x + 5cos2x + 2.1. 157/252. 25/1573. 125/574. 57/125 |
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Answer» Correct Answer - Option 1 : 157/25 Given: sinx = 3/5 Formula Used: sin2θ + cos2θ = 1 Calculations: 3sin2x + 5cos2x + 2 ⇒ 3sin2x + 5(1 - sin2x) + 2 = 7 - 2sin2x Now, sinx = 3/5 ⇒ 7 - 2sin2x = 7 - 2 × (3/5)2 ⇒ 7 - 2sin2x = 157/25 ∴ The value of (3sin2x + 5cos2x + 2) is 157/25. |
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