1.

If sinx = 3/5, then find the value of 3sin2x + 5cos2x + 2.1. 157/252. 25/1573. 125/574. 57/125

Answer» Correct Answer - Option 1 : 157/25

Given:

sinx = 3/5

Formula Used:

sin2θ + cos2θ = 1

Calculations:

3sin2x + 5cos2x + 2

⇒ 3sin2x + 5(1 - sin2x) + 2 = 7 - 2sin2

Now, sinx = 3/5

⇒ 7 - 2sin2x = 7 - 2 × (3/5)2

⇒ 7 - 2sin2x = 157/25

∴ The value of (3sin2x + 5cos2x + 2) is 157/25.



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