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If sinx = √5/3 and 0 < x < π/2, find the values of cos 2x |
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Answer» Given: sinx = \(\frac{\sqrt{5}}{3}\) To find: cos2x We know that, cos2x = 1 – 2sin2x Putting the value, we get cos2x = 1 - 2\((\frac{\sqrt{5}}{3})^{2}\) cos2x = 1 - 2 x \(\frac{5}{9}\) cos2x = 1 - \(\frac{10}{9}\) cos2x = \(\frac{9\,-\,10}{9}\) ∴ cos2x = -\(\frac{1}{9}\) |
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