InterviewSolution
`2NPI-(pi)/3lt x lt 2n pi +(4pi)/3, n in Z``2np -(pi)/6lt x lt 2npi+(7pi)/6, n in Z``2npi-(pi)/6 lt XLT 2npi+(5PI)/6, n in Z``2npi-(pi)/3lt xlt 2npi+(2PI)/3, n in Z`
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