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If six students, including two particular students A and B, stand in a row, then the probability that A and B are separated with one student in between them isA. `8//15`B. `1//5`C. `2//15`D. `4//15` |
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Answer» Correct Answer - D Total number of ways in which 6 students can stand in row is 6!. One student can stand between A and B in `.^(4)C_(1)xx2!` ways. Considering these three as one individual we have 4 students who can stand in a row in 4! Ways. Therefore, number of ways in which one student is there between A and B and is `.^(4)C_(1)xx2!xx4!`. Hence, required probability `=(.^(4)C_(1)xx2!xx4!)/(6!)=(4)/(5)` |
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